Assertion: We find midpoints of a class interval with the following formula.
$\frac{u p p e r c l a s s l i m i t + l o w e r c l a s s l i m i t}{2}$
Reason: To draw frequency polygons independently without drawing histogram it is required to have the class mark.
Which of the following is correct?

Both A and R are true and R is the correct explanation of A

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Both A and R are true but R is not the correct explanation of A

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A is true and R is false

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A is false and R is true

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Solution

The correct option is B
Both A and R are true but R is not the correct explanation of A

A: By definition, this is true
R: By definition, this is true
To draw the frequency polygon one has to find the class mark.
Hence, R is not the correct explanation of A.

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Assertion: We find midpoints of a class interval with the following formula.
$\frac{u p p e r c l a s s l i m i t + l o w e r c l a s s l i m i t}{2}$

Reason: To draw frequency polygons independently without drawing histogram it is required to have the class mark.

Which of the following is correct?

If we draw a histogram for the following frequency distribution, what will be the height of the bar for the class interval 15 - 30?

To draw a frequency polygon, we have to first draw a histogram.

The frequency polygon of a frequency distribution is shown below.

Answer the following about the distribution from the histogram.

(i) What is the frequency of the class interval whose class mark is 15?

(ii) What is the class interval whose class mark is 45?

(iii) Construct a frequency table for the distribution.

Q. If class sizes are different in a given frequency distribution then to draw the histogram it is required to

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Assertion: We find midpoints of a class interval with the following formula. upper class limit+lower class limit2 Reason: To draw frequency polygons independently without drawing histogram it is required to have the class mark. Which of the following is correct?

The correct option is B Both A and R are true but R is not the correct explanation of A A: By definition, this is true R: By definition, this is true To draw the frequency polygon one has to find the class mark. Hence, R is not the correct explanation of A.

Assertion: We find midpoints of a class interval with the following formula.
$\frac{u p p e r c l a s s l i m i t + l o w e r c l a s s l i m i t}{2}$
Reason: To draw frequency polygons independently without drawing histogram it is required to have the class mark.
Which of the following is correct?

The correct option is B
Both A and R are true but R is not the correct explanation of A

A: By definition, this is true
R: By definition, this is true
To draw the frequency polygon one has to find the class mark.
Hence, R is not the correct explanation of A.