Assertion :When capacitive reactance is smaller than the inductive reactance in $L - C - R$ circuit, emf leads the current. Reason: The phase angle is the angle between the alternating emf and alternating current of the circuit.

Both Assertion and Reason are correct and Reason is the correct explanation for Assertion

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Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion

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Assertion is correct but Reason is incorrect

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Both Assertion and Reason are incorrect

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Solution

The correct option is B Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
The phase angle for L-C-R circuit is given by
$t a n ϕ = \frac{X_{L} - X_{C}}{R} = \frac{ω L - \frac{1}{ω C}}{R}$
When $X_{L} > X_{C}$ , $t a n ϕ$ is positive, that is, $ϕ$ is from $0$ to $\frac{π}{2}$ .
Hence emf leads current.

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Assertion :When capacitive reactance is smaller than the inductive reactance in L−C−R circuit, emf leads the current. Reason: The phase angle is the angle between the alternating emf and alternating current of the circuit.

The correct option is B Both Assertion and Reason are correct but Reason is not the correct explanation for AssertionThe phase angle for L-C-R circuit is given bytanϕ=XL−XCR=ωL−1ωCRWhen XL>XC, tanϕ is positive, that is, ϕ is from 0 to π2.Hence emf leads current.

Assertion :When capacitive reactance is smaller than the inductive reactance in $L - C - R$ circuit, emf leads the current. Reason: The phase angle is the angle between the alternating emf and alternating current of the circuit.