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Standard IX

History

Inventions during the Industrial Revolution

Assume a cycl...

Question

Assume a cyclic process $A B C A$ for an ideal gas. In $A B$ , $B C$ and $C A$ process $50 J$ , $20 J$ and $5 J$ heat is supplied to an ideal gas. In process $A B$ internal energy of gas increases by $60 J$ and in process $B C$ work done by gas is $30 J$ . The increase in internal energy of gas in process $C A$ is:

50 J

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55 J

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75 J

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- 50 J

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Solution

The correct option is D $- 50 J$
Formula used: $Δ Q = Δ U + Δ W$
Given,
$Δ Q_{A B} = 50 J$
$Δ Q_{B C} = 20 J$
$Δ Q_{C A} = 5 J$
$Δ U_{A B} = 60 J$
$Δ W_{B C} = 30 J$
From the First law of thermodynamics,
$d Q$ $d W$ $d U$

$A \to B$ $50 J$ $- 10 J$ $60 J$

$B \to C$ $20 J$ $30 J$ $- 10 J$

$C \to A$ $5 J$ $55 J$ $- 50 J$

$A \to B \to C \to A$ $75 J$ $75 J$ $0$

Final Answer: (𝒃)


$A \to B$	$50 J$	$- 10 J$	$60 J$
$B \to C$	$20 J$	$30 J$	$- 10 J$
$C \to A$	$5 J$	$55 J$	$- 50 J$
$A \to B \to C \to A$	$75 J$	$75 J$	$0$

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Assume a cyclic process ABCA for an ideal gas. In AB, BC and CA process 50 J, 20 J and 5 J heat is supplied to an ideal gas. In process AB internal energy of gas increases by 60 J and in process BC work done by gas is 30 J. The increase in internal energy of gas in process CA is:

The correct option is D −50 JFormula used: ΔQ=ΔU+ΔW Given, ΔQAB=50 J ΔQBC=20 J ΔQCA=5 J ΔUAB=60 J ΔWBC=30 J From the First law of thermodynamics, dQ dW dU A→B 50 J −10 J 60 J B→C 20 J 30 J −10 J C→A 5 J 55 J −50 J A→B→C→A 75 J 75 J 0 Final Answer: (𝒃)