CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Millikan's Oil Drop Experiment

Assume that a...

Question

Assume that a box full of electrons had a total charge of $- 96368 C$ . The number of moles of eletcrons present inside the box is
$Given : e = - 1.6 \times 10^{- 19} C$

Open in App

Solution

Charge on an electron $= - 1.6 \times 10^{- 19} C$
Total charge conatined $= - 96368 C$
Number of electrons $= \frac{magnitude of total charge}{Magnitude of charge on one elctron}$

$= \frac{96368 C}{1.6 \times 10^{- 19} C} = 6.023 \times 10^{23}$

So, the box has 1 mol of electrons.

Suggest Corrections

thumbs-up

0

Similar questions

Q. The total charge in coulombs, of all the electrons in three gram mole hydrogen atom is equal to

- x \times 10^{3} C

. Find the value of

x

Use avogadro number,

N_{A} = 6 \times 10^{23}

and charge on electron

e = - 1.6 \times 10^{- 19} C

Q. The magnitude of charge of a single electron or proton is

1.6 \times 10^{- 19} C

. What is the net charge of a particle that has

20

22

Q. The charge on a proton is +1.6 × 10⁻¹⁹ C and that on an electron is −1.6 × 10⁻¹⁹ C. Does it mean that the electron has 3.2 × 10⁻¹⁹ C less charge than the proton?

The magnitude of the charge of a single electron or a proton is $1.6 \times 10^{- 19} C$ .
What is the net charge of an object that has 20 electrons and 22 protons?

Q. A potential difference of

400

volt is maintained across a conductor of resistance

200 o h m

. Calculate the number of electrons flowing through it in one second. Charge on electron,

e = 1.6 \times 10^{- 19} C

View More

Join BYJU'S Learning Program

explore_more_icon

Explore more

Millikan's Oil Drop Experiment

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon