assume that a car is able to stop with a retardation of 8ms^-2 and that a driver can react to an emergency in 0.5s calculate the overall stopping distance of the car for a speed of 60kmh^-1 of the car

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Solution

Dear Student ,
Initial velocity = u = 60 km/h = 16.67 m/s
Final velocity = v = 0
time taken = t = 0.5 s
Retardation = a =8 m/s²

$S o s t o p p i n g d i s \tan c e i s, s = u t - \frac{1}{2} a t^{2} = (16 \cdot 67 \times 0 \cdot 5) - (\frac{1}{2} \times 8 \times 0 \cdot 25) = 7 \cdot 335 m$
Regards

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assume that a car is able to stop with a retardation of 8ms-2 and that a driver can react to an emergency in 0.5s calculate the overall stopping distance of the car for a speed of 60kmh​-1 of the car

Dear Student , Initial velocity = u = 60 km/h = 16.67 m/s Final velocity = v = 0 time taken = t = 0.5 s Retardation = a =8 m/s2 So stopping distance is ,s=ut-12at2=16·67×0·5-12×8×0·25=7·335 m Regards

assume that a car is able to stop with a retardation of 8ms^-2 and that a driver can react to an emergency in 0.5s calculate the overall stopping distance of the car for a speed of 60kmh^-1 of the car