Question

Assume that a drop of liquid evaporates by decrease in its surface energy. so that its temperature remains unchanged What should be the minimum radius of the drop for this possible The surface tension is T. density of liquid is $\rho$ and L is talent heat of vaporization

• A. $\rho L/T$
• B. $\sqrt{T/\rho L}$
• C. $T/\rho L$
• D. $2T/\rho L$

Answer 1

The correct option is D $2T/\rho L$

Heat of vaporization $=$ Surface energy released

$Ldm=TdA$

$4L\rho \pi r^{2}dr=T8\pi rdr$

$r=\frac{2T}{\rho L}$

Hence,

option $\left(D\right)$ is correct answer.