Assume that boy and girl babies are equally likely. If a couple have three children, find the probability that at least one is a boy. (Give the answer up to 3 decimal places)

0.875

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0.785

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0.578

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0.75

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Solution

The correct option is A
0.875

The complimentary event is having all three girls, which has only one outcome associated with it: GGG out of a possible 8 outcomes. The 8 possible outcomes are:

{BBB,BBG,BGG,BGB,GBB,GBG,GGB,GGG}.

So the probability of the complementary event is $\frac{1}{8}$ .
Hence, the required probability is = $1 - \frac{1}{8}$ = $\frac{7}{8}$ = $0.875$

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