Question

Assume that if the shear stress in steel exceeds about $4.00\times {10}^8{\text{N/m}}^2$, the steel ruptures. If the shearing force necessary to rupture a steel bolt of diameter $1.00\text{cm}$ is $x\times {10}^4\text{N}$, then $x$ is
[Take $\pi =3.14$ and answer upto two decimal places]

Answer 1

Shear force needed to rupture a bolt
$F$= Stress$\times \left(A\right)$
$\Rightarrow F=(4.00\times {10}^8{\text{N/m}}^2)\times \pi (5.00\times {10}^{-3}\text{m}{)}^2$
$=3.14\times {10}^4\text{N}$