Question

Assume that if the shear stress in steel exceeds about $4.00\times {10}^8{\text{N/m}}^2$, the steel ruptures. If the shearing force necessary to rupture a steel bolt of diameter $1.00\text{cm}$ is $n\pi \times {10}^4\text{N}$, then find $n$

• A. 1.0
• B. 1.00
• C. 1

Answer 1

Answer: (A), (B), (C)

Shear force needed to rupture a bolt
$F$= Stress$\times \left(A\right)$
$\Rightarrow F=(4.00\times {10}^8{\text{N/m}}^2)\times \pi (5.00\times {10}^{-3}\text{m}{)}^2$
$=\pi \times {10}^4\text{N}$

Comparing this with the data given in the question we get,
$n=1$