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Question

Assume that impure copper contains only Fe,Au and Ag as impurities. After passage of 140 ampere for 482.5 sec, the mass of anode decreased by 22.260 g and the cathode increased in mass by 22.011 g. Calculate the percentage of iron and percentage of copper originally present.

A
Fe = 3% Cu = 93%
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B
Fe = 2.5% Cu = 89%
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C
Fe = 3.5% Cu = 93%
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D
None of these
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Solution

The correct option is D None of these
Percentage of Iron present is given by

%Fe=22.26022.01122.260×100=1.12%

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