wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Assume that impure copper contains only Fe,Au and Ag as impurities. After passage of 140 ampere for 482.5 sec, the mass of anode decreased by 22.260 g and the cathode increased in mass by 22.011 g. Calculate the percentage of iron and percentage of copper originally present.

A
Fe = 3% Cu = 93%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Fe = 2.5% Cu = 89%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Fe = 3.5% Cu = 93%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D None of these
Percentage of Iron present is given by

%Fe=22.26022.01122.260×100=1.12%

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Faraday's Laws
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon