The correct option is D The function g is onto
If f and g are inverse, then (fog)(x)=x
f′[g(x)]g′(x)=1
If f is increasing
⇒f′>0
⇒ Sign of g′ is also positive.
Therefore, option (a) is correct.
If f is decreasing
⇒f′<0
⇒ Sign of g′ is negative.
Therefore, option (b) is false.
Since, f has an inverse.
f is bijective
⇒f is injective Therefore, option (c) is correct. Inverse of a bijective mapping is bijective.
⇒g is also bijective g is onto
Therefore, option (d) is correct.
Hence, (a),(c) and (d) are the correct.