Question

Assume that the nuclear mass is of the order of ${10}^{-27}$kg and the nuclear radius is of the order of ${10}^{-15}$m.Then, nuclear density is of the order of :

• A. 10${}^2$Kg/m${}^3$
• B. 10${}^{10}$kg/m${}^3$
• C. 10${}^{17}$Kg/m${}^3$
• D. 10${}^{31}$kg/m${}^3$

Answer 1

Answer: (C)

10${}^{17}$Kg/m${}^3$

$R={10}^{-15}m,Mass={10}^{-27}kg$
Density $=\frac{{10}^{-27}}{\frac{4}{3}\pi ({10}^{-15}{)}^3}$
$=2.39\times {10}^{17}\frac{kg}{m^3}$