Question

Assume that the nucleus of the fluorine atom is a sphere with a radius of $5\times {10}^{-13}cm$. The density of the fluorine nucleus is:

• A. $0.06\times {10}^{15}g/mL$
• B. $0.6\times {10}^{15}g/mL$
• C. $6\times {10}^{15}g/mL$
• D. None of these

Answer 1

The correct option is A $0.06\times {10}^{15}g/mL$

Given:- Radius $=5\times {10}^{-13}cm$

To find : Density

Formula: Density $=\frac{Mass}{Volume}$

$IF$ nucleus $=\frac{19g/mol}{6.022\times {10}^{23}atoms/mol}$

$=3.16\times {10}^{-23}g/atoms$

Volume of sphere $=4/3\pi r^3$

$=\left(\frac{4}{3}\right)\left(3.14\right)(5\times {10}^{-13}cm{)}^3$

$=5.24\times {10}^{37}c{m}^3$

Density $=\frac{3.16\times {10}^{-23}g/atom}{5.24\times {10}^{-37}c{m}^3}$

$=6.02\times {10}^{13}g/c{m}^3$

On changing decimals $=0.06\times {10}^{15}g/mL$

with $cm\to mL$