Assume that two oxides of a metal contain 25% and 40% of oxygen by weight respectively. Find the ratio of weights of metal combining with fixed mass of oxygen.

2 : 1

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1 : 2

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1 : 3

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4 : 1

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Solution

The correct option is B 2 : 1
$L e t o x i d e s t o b e M_{2} O_{x} a n d N_{2} O_{y} r e s p e c t i v e l y A / Q \frac{16 x}{16 x + 2 m} = 0.25 a n d \frac{16 y}{16 y + 2 n} = 0.4 S o l v i n g b o t h e q u a t i o n s s e p a r a t e l y, w e g e t m = 24 x n = 12 y i f, w e i g h t o f o x y g e n i s s a m e f o r b o t h o x i d e s, x = y H e n c e, \frac{m}{n} = \frac{2}{1} m : n = 2 : 1 (A n s)$

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