Assume that you have a sample of a gas containing H2,HD and D2 that you want to separate into pure components (H=1HandD=2H). What are the relative rates of diffusion of the three gases according to Graham’s law?
A
H2>HD>D2
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B
D2>HD>H2
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C
D2>H2>HD
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D
All have same rate
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Solution
The correct option is AH2>HD>D2 According to Graham's law of diffusion, Rate of diffusion=1√Molar mass
Since D2 is the heaviest of the three molecules, it will be the slowest to diffuse and let us call its relative rate as 1.00. We can then compare the rate of diffusion of HD and H2 with D2 by using Graham's law of diffusion.
Comparing HD with D2 we have, Rate ofHDdiffusionRate ofD2diffusion=√Molar mass ofD2Molar mass ofHD=√4.03.0=1.15
Comparing H2 with D2 we have, Rate ofH2diffusionRate ofD2diffusion=√Molar mass ofD2Molar mass ofH2=√4.02.0=1.41
Thus, the relative rates of diffusion are H2(1.41)>HD(1.15)>D2(1.00)