Question

Assume the cell has a diploid number of $4$. If the above chromosomes are in the tetrad or bivalent stage of meiosis, which statement below is correct about the events of anaphase I?

• A. Two of the tetrads will go to one cell, and two will go to the other.
• B. Sister chromatids will break apart and each will go in one of four cells.
• C. One member of each homologous pair will go into each of the two cells.
• D. The tetrads will separate but each new cell will still be diploid since each chromosome has two chromatids.

Answer 1

The correct option is C One member of each homologous pair will go into each of the two cells.

The diploid cell with chromosomes 4 contains 2 pairs of homologous (maternal and paternal) chromosomes. These DNA replicates and there is an increase in the number of chromatids which are known as bivalents with two sister chromatids in each chromosome. In the anaphase I, there is a separation of the chromosome without breaking. One of the homologous chromosomes will move towards opposite poles and get into one of each cell.

Thus, the correct answer is option C.