Assume X , Y , Z , W and P are matrices of order , and respectively. The restriction on n , k and p so that will be defined are: A. k = 3, p = n B. k is arbitrary, p = 2 C. p is arbitrary, k = 3 D. k = 2, p = 3

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Solution

It is given that the matrices X, Y, Z, W and P are of the order 2×n, 3×k, 2×p, n×3 and p×k respectively.

Since, the matrix P is given of the order p×k and Y is given of the order 3×k, so, the matrix PY will be defined if k=3.

Since the matrices W and Y are of the order n×3 and 3×k respectively, and it is observed that the number of columns in W are equal to the number of rows in Y, then, matrices WY can be defined of the order n×k.

Now, the matrices PY and WY can be added only when their orders will be same.

Since, PY is of order p×k and WY is order ( n×k ), so, the value must have p=n.

Thus, PY+WY will be defined when the restrictions on n, k and p are k=3 and p=n.

Therefore, option (A) is correct.

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Similar questions

Assume X, Y, Z, W and P are matrices of order, and respectively. The restriction on n, k and p so that will be defined are:

A. k = 3, p = n

B. k is arbitrary, p = 2

C. p is arbitrary, k = 3

D. k = 2, p = 3

Assume X,Y,Z, W and P are matrices of orders $2 \times n, 3 \times k, 2 \times p, n \times 3 a n d p \times k$ respectivley.

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(a)k=3, p=n
(b)k is arbirary, p=2
(c)p is arbitary
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A p × 2 B 2 × n C n × 3 D p × n

Assume X,Y,Z, W and P are matrices of orders $2 \times n, 3 \times k, 2 \times p, n \times 3 a n d p \times k$ respectivley. Choose the correct answer in Q.21 and Q.22.
If n = p, then the order of the matrix 7X-5Z is
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Q. The restriction on

n, k

and

p

so that

P Y + W Y

will be defined are:

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