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Question

Assuming 100% ionisation of BaCl2 (aq), what will be the value of van't Hoff factor?

A
1.5
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B
3
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C
2
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D
4
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Solution

The correct option is B 3
van't Hoff factor (i)=Number of molecules (actual)Number of molecules (expected)


For 100% ionisation, van't Hoff factor is equal to the number of particles in which 1 ​molecule of electrolyte dissociates​.

BaCl2Ba+2+2Cl
i=3

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