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Byju's Answer
Standard XII
Chemistry
Van't Hoff Factor
Assuming 25
Question
Assuming 25% ionisation in aqueous solution, what will be the van't Hoff factor for
N
a
C
l
?
A
0.75
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B
1
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C
1.25
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D
0.25
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Solution
The correct option is
C
1.25
N
a
C
l
(
a
q
)
⇌
N
a
+
+
C
l
−
I
n
i
t
i
a
l
l
y
:
C
0
0
E
q
b
:
C
−
C
α
C
α
C
α
i
=
No. of moles after dissociation
No. of moles before dissociation
i
=
C
−
C
α
+
C
α
+
C
α
C
i
=
C
+
C
α
C
=
1
+
α
Given that :
α
=
0.25
i
=
1
+
(
0.25
)
i
=
1.25
Suggest Corrections
2
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