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Question

Assuming 25% ionisation in aqueous solution, what will be the van't Hoff factor for NaCl ?

A
0.75
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B
1
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C
1.25
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D
0.25
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Solution

The correct option is C 1.25
NaCl (aq)Na++ClInitially: C 0 0Eqb: CCα Cα Cα

i=No. of moles after dissociationNo. of moles before dissociation

i=CCα+Cα+CαCi=C+CαC=1+α
Given that :
α=0.25
i=1+(0.25)i=1.25

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