Assuming all spheres have equal radii and are close packed in two dimension. The correct relation between the packing fractions of the structure given below is

n_{1} = n_{2} = n_{3}

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n_{1} > n_{2} > n_{3}

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n_{2} > n_{3} > n_{1}

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n_{1} > n_{3} > n_{2}

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Solution

The correct option is A $n_{1} = n_{2} = n_{3}$
Every triangular region has a packing efficiency of 90% approximately.

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Similar questions

	Column I		Column II
(i)	Square close packing in two dimension	(p)	Triangular voids
(ii)	Hexagonal close packing in two dimensions	(q)	Pattern of spheres is repeated in every fourth layer
(iii)	Hexagonal close packing in three dimension	(r)	Coordination number=4
(iv)	Cubic close packing in three dimension	(s)	Pattern of spheres is repeated in alternate layers

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