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Question

Assuming CH3andCH3CO to be under steady state (i.e. the rate of formation and rate of consumption of an intermediate species are equal), derive expressions for (i) [CH3] and (ii) [CH3CO] in terms of [CH3CHO].

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Solution

i)d[CH3]dt=k1[CH3CHO]k2[CH3CHO][CH3]+k3[CH3CO]2k4[CH3]2=0ii)d[CH3CO]dt=k2[CH3CHO][CH3]kc[CH3CO]=0[CH3]=k12k4[CH3CHO]1/2[CH3CO]=k2k3k12k4[CH3CHO]1/2

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