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Standard XII

Chemistry

Bond Length

Assuming C6...

Question

Assuming $C_{6} H_{6}$ ring a regular hexagon and $C - I$ bond lies on the line through the centre of hexagon. If the distance between adjacent carbon is $1.40 ˚ A$ , and covalent radius of iodine and carbon atoms are $1.33 ˚ A$ and $0.77 ˚ A$ respectively, then the $I - I$ distance in $˚ A$ is_________.

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Solution

The distance between two iodine atoms is $2 (1.33 + 0.77) + 1.40 + 2 (1.4 t a n 30) = 4.2 + 1.40 + 2 (1.4 \times 0.577) = 7.2 \approx 7$ . Hence, the given statement is correct.

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Similar questions

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Assuming C6H6 ring a regular hexagon and C−I bond lies on the line through the centre of hexagon. If the distance between adjacent carbon is 1.40˚A, and covalent radius of iodine and carbon atoms are 1.33˚A and 0.77˚A respectively, then the I−I distance in ˚A is_________.

The distance between two iodine atoms is 2(1.33+0.77)+1.40+2(1.4tan30)=4.2+1.40+2(1.4×0.577)=7.2≈7. Hence, the given statement is correct.

The distance between two iodine atoms is $2 (1.33 + 0.77) + 1.40 + 2 (1.4 t a n 30) = 4.2 + 1.40 + 2 (1.4 \times 0.577) = 7.2 \approx 7$ . Hence, the given statement is correct.