Assuming $C O_{2}$ to be van der waals gas, calculate its Boyle temperature. Given $a = 3.59 a t m L^{2} m o l^{- 2} b = 0.0427 L m o l^{- 1}$

Boyle temperature $T_{b}$ is

873 K

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924 K

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1024 K

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1226 K

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Solution

The correct option is C
1024 K

$1024 K$

$T_{b} = \frac{a}{R_{b}}$

Now add:

Solution of 2-46............

$T_{B} = 1024 K$

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Assuming CO2 to be van der waals gas, calculate its Boyle temperature. Given a=3.59 atm L2 mol−2b=0.0427 L mol−1 Boyle temperature Tb is

The correct option is C 1024 K 1024 K Tb=aRb Now add: Solution of 2-46............ TB=1024 K

Assuming $C O_{2}$ to be van der waals gas, calculate its Boyle temperature. Given $a = 3.59 a t m L^{2} m o l^{- 2} b = 0.0427 L m o l^{- 1}$

Boyle temperature $T_{b}$ is

The correct option is C
1024 K

$1024 K$

$T_{b} = \frac{a}{R_{b}}$

Now add:

Solution of 2-46............

$T_{B} = 1024 K$