Assuming complete ionization, calculate freezing point of solution prepared by adding 6g Glauber's salt Na2SO4.10H2O in 0.1 kg of water ?(Given Kf = 1.86 K kg/mol , Atomic masses, Na=23,O=16,S=32,H=1 )
Step 1:
The chemical equation for the given reaction is as follows:
Na2SO4⟶2Na++SO2−4
So, three particles have been formed after complete dissociation.
The molar mass of Na₂SO₄.10H₂O will be = 46 + 32 + 64 + (10 x 18) = 322
Step 2:
The weight of water Wa = 0.1 kg = 100 g
The weight of the solute (Glauber's salt) Wb = 6.0 g
Given that, Kf = 1.86 K kg mol⁻¹
i (Van't Hoff factor) = 3
Step 3:
According to the relation, DTf=KfMB×WaWb×1000×i
= 1.86322×6.0100×1000×3 = 1.039 K
So, the freezing point will be calculated as = 273 - 1.039 K = 271.96 K