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Gibb's Energy and Nernst Equation

Assuming ΔH...

Question

Assuming $Δ H^{o}$ and $S^{o}$ do not change with temperature. Calculate, the boiling point of liquid $A$ using the thermodynamic data given below:
Therodynamic data $A (l)$ $A (g)$
$Δ H^{o} (k J / m o l)$ $- 130$ $- 100$
$S^{o} (J K^{- 1} {m o l}^{- 1})$ $100$ $200$

300 K

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130 K

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150 K

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50 K

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Solution

The correct option is A $300 K$
$Δ H = Δ H_{A (g)}^{o} - Δ H_{A (l)}^{o} = - 100 - (- 130) = 30 k J$
$Δ S = Δ S_{A (g)}^{o} - Δ S_{A (l)}^{o} = 200 - 100 = 100 J K^{- 1} {m o l}^{- 1}$
At equilibrium, $Δ G = Δ H - T Δ S$
$T = \frac{Δ H}{Δ S} = 300 K$

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