Question

Assuming $H_{2}S{O}_4$ to be completely ionised, the pH of a $0.05M$ aqueous solution of sulphuric acid is approximately:

• A. $0.01$
• B. $0.005$
• C. $2$
• D. $1$

Answer 1

The correct option is D $1$

$pH=-log\left[H^{+}\right]$

Here. as acid i.e. sulphuric acid is dibasic.

So, $\left[H^{+}\right]=0.05\times 2=0.1$

So, pH = $-log0.1=1$