Assuming ideal behaviour- the magnitude of log K for the following reaction at 25oC is x-10-1- The value of x is integer answer3HC- CHg-C6H6l-Given-fG0HC- CH-2-04-105Jmol-1- Gf0C6H6 -1-24-105J mol-1-R-8-314J K-1mol-1-

Answer : 855 nbsp;3CH≡ CH(g)⇌C_6H_6(l) ΔG^0=Δ G_f^0(C_6H_6) 3Δ G_f^0(CH≡ CH) = 1.24×10^5 3( 2.04×10^5) =4.88×10^5J mol^ 1 ΔG^0= RT ln K = 2.303RT log ...

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Standard XII

Chemistry

Enthalpy of Combustion

Assuming idea...

Question

Assuming ideal behaviour, the magnitude of log K for the following reaction at $25^{o} C$ is $x \times 10^{- 1}$ . The value of x is _____(integer answer)

$3 H C \equiv C H_{(g)} ⇌ C_{6} H_{6 (l)}$

$[G i v e n : Δ_{f} G^{0} (H C \equiv C H) = - 2.04 \times 10^{5} J m o l^{- 1};$

$Δ G_{f}^{0} (C_{6} H_{6}) = - 1.24 \times 10^{5} J m o l^{- 1}; R = 8.314 J K^{- 1} m o l^{- 1}]$

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Solution

Answer : 855

$3 C H \equiv C H (g) ⇌ C_{6} H_{6} (l)$

$Δ G^{0} = Δ G_{f}^{0} (C_{6} H_{6}) - 3 Δ G_{f}^{0} (C H \equiv C H)$

$= - 1.24 \times 10^{5} - 3 (- 2.04 \times 10^{5})$

$= 4.88 \times 10^{5} J m o l^{- 1}$

$Δ G^{0} = - R T l n K$

$= - 2.303 R T l o g K$

$l o g K = - \frac{4.88 \times 10^{5}}{2.303 \times 8.314 \times 298}$

$| l o g K | = \frac{4.88 \times 10^{5}}{2.303 \times 8.314 \times 298}$
$| l o g K | = 85.5$
$x \times 10^{- 1} = 85.5$
x = 855

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Assuming ideal behaviour, the magnitude of log K for the following reaction at 25oC is x×10−1. The value of x is _____(integer answer) 3HC≡CH(g)⇌C6H6(l) [Given:ΔfG0(HC≡CH)=−2.04×105Jmol−1; ΔG0f(C6H6)=−1.24×105Jmol−1;R=8.314JK−1mol−1]

Answer : 855 3CH≡CH(g)⇌C6H6(l) ΔG0=ΔG0f(C6H6)−3ΔG0f(CH≡CH) =−1.24×105−3(−2.04×105) =4.88×105J mol−1 ΔG0=−RT ln K =−2.303RT log K log K=−4.88×1052.303×8.314×298 |log K|=4.88×1052.303×8.314×298 |log K|=85.5 x×10−1=85.5 x = 855