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Standard IX

Chemistry

Faraday's Second Law

Assuming no c...

Question

Assuming no change in volume, the time required to obtain solution of $p H = 12$ by electrolysis of $50 m l . 0. 1 M N a C l$ (using current of 0.5 amp) will be

65 sec

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96.5 sec

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965 sec

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9.65 sec

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Solution

The correct option is B 96.5 sec
$[H^{+}] = 10^{- 12} M$
$∴ [O H^{-}] = 10^{- 2} M$
Number of moles of $N a O H$ is $50 m L$ solution $= \frac{M V}{1000} = \frac{10^{- 2} \times 50}{1000}$
$= 5 \times 10^{- 4}$
Mass of $N a O H$ in the solution $= 5 \times 10^{- 4} \times 40 = 2 \times 10^{- 2} g$
$W = \frac{I t E}{96500}$
$2 \times 10^{- 2} = \frac{0.5 \times t \times 40}{96500}$
$t = 96.5 s e c$

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Assuming no change in volume, the time required to obtain solution of pH=12 by electrolysis of 50ml. 0. 1M NaCl (using current of 0.5 amp) will be

The correct option is B 96.5 sec[H+]=10−12 M ∴[OH−]=10−2M Number of moles of NaOH is 50 mL solution =MV1000=10−2×501000 =5×10−4 Mass of NaOH in the solution =5×10−4×40=2×10−2 g W=ItE96500 2×10−2=0.5×t×4096500 t=96.5 sec

Assuming no change in volume, the time required to obtain solution of $p H = 12$ by electrolysis of $50 m l . 0. 1 M N a C l$ (using current of 0.5 amp) will be