The correct option is D If we change the reference point, the potential difference between 2 points will not change.
In case of spherical shell, we select a gaussian surface concentric with the shell of radius r(r>R).
So, ∮→E.→ds=E(4πr2)cos0
According to Gauss law,
E(4πr2)cos0=Qenclosedϵo
Since charge enclosed inside the spherical shell is zero.
So, E=0, but V is not zero.
For a shell,
Vcenter=Vsurface=kQR
For a sphere,
Vcenter=3kQ2R
Self energy of a dipole is negative since self energy is the total binding energy.
When we change the reference point, the potential related to each point changes while the potential difference between 2 points remains same.