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Standard XII

Chemistry

Chemical Reactivity

Assuming same...

Question

Assuming same pressure in each case, calculate the mass of hydrogen required to inflate a ballon to a certain volume V at 127°C if 8 g of He is required to inflate the balloon to half its volume, at 27°C.

Please explain the solution well.

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Solution

Given:
Volume = V
mass of He (w) = 3.5 g
T of Hydrogen = 273 + 100 = 373K
T of Helium = 25 + 272 = 298K
Now,
For Hydrogen, P x V = (w/m)RT
P x V = (w/2) R x 373 ------------ eqn (1)
For Helium, P x V/2 = (w/m)RT
P x V/2 = (35/4) R x 298 ------------- eqn (2)
Solving eqn (1) & (2), we get
mass of hydrogen = 2.8 g

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Assuming same pressure in each case, calculate the mass of hydrogen required to inflate a ballon to a certain volume V at 127°C if 8 g of He is required to inflate the balloon to half its volume, at 27°C. Please explain the solution well.

Assuming same pressure in each case, calculate the mass of hydrogen required to inflate a ballon to a certain volume V at 127°C if 8 g of He is required to inflate the balloon to half its volume, at 27°C.

Please explain the solution well.