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Question

assuming that a capacitor is disconnected from the charging battery explain how the capacitance potential difference across the plates and energy stored in a parallel plate capacitor change when a medium of dielectric constant K is introduced between the plates

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Dear Student
When a dielectric material is introduced between the plates and when a dielectric material is placed between the plates of parallel plate capacitor then due to polarisation of charges on either side of the dielectric it produces an electric field of its own which acts in a direction opposite to that of the field due when dielectric material is inserted between parallel plates the capacitance increases and the new capacitance C' is given by C' = k×C, where k is dielectric constant. Charge Q remains same. Hence potential difference reduces and the new value of potential difference is V/k .
Regards

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