Assuming that at S.T.P. gas A has a density of 0.09 gram per litre and gas B has a density of 1.43 gram per litre, the ratio between the rates of diffusion of A and B is:

1:16

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16:1

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2:1

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4:1

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Solution

The correct option is B 4:1
We know from Graham's law of diffusion:

$\frac{r_{A}}{r_{B}} = \sqrt{\frac{d_{B}}{d_{A}}}$

$\frac{r_{A}}{r_{B}} = \sqrt{\frac{1.43}{0.09}} \approx 4 : 1$

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