Assuming that heat released by water is entirely used to raise the temperature of calorimeter 15oC to 45oC, calculate the specific heat capacity of copper. (Specific heat capacity of water =4200Jkg−1oC−1
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Solution
Heat energy absorbed by calorimeter = mSt =0.16×S×(45−15)=4.8S Now, Heat given = Heat taken 4.8S=2100⇒S=21004.8=437.5Jkg−1oC−1