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Question

Assuming that heat released by water is entirely used to raise the temperature of calorimeter 15oC to 45oC, calculate the specific heat capacity of copper. (Specific heat capacity of water =4200Jkg1oC1

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Solution

Heat energy absorbed by calorimeter = mSt
=0.16×S×(4515)=4.8S
Now, Heat given = Heat taken
4.8S=2100S=21004.8=437.5Jkg1oC1

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