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Quantitative Aptitude

Divisibility Rule for Composite Numbers

Assuming that...

Question

Assuming that no two consecutive digits are same, the number of n is

A

n!

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B

9!

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C

9^{n}

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D

n^{9}

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Solution

The correct option is A $n!$
when no two consecutive digits are same, then
this multiplying them, gives n!
Eg :- $5! = 5 \times 4 \times 3 \times 2 \times 1 = 120$

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