Assuming that $O_{2}$ molecule is spherical in shape with radius 2 A, the percentage of the volume of $O_{2}$ molecules to the total volume of gas at S.T.P. is :

0.09

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0.9

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0.009

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Solution

The correct option is A 0.09
$\begin{matrix} Volume of O_{2} molecule = \frac{4}{3} π r^{3} = V_{1} V_{1} = \frac{4}{3} π \times 8 \times 10^{- 30} m^{3} \end{matrix}$
$\begin{matrix} volume of O_{2} molecule at S T P V_{2} = \frac{22.4}{N_{A}} \times 10^{- 3} m^{3} \end{matrix}$
$\begin{matrix} (N_{A} = 6.023 \times 10^{23}) \frac{Vol. of O_{2} molecule}{{Vol. of O}_{2} molecule at STP} = \frac{V_{1}}{V_{2}} = 0.09 \end{matrix}$

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