Assuming that $O_{2}$ molecule is spherical in shape with radius $2 ˚ A$ , the percentage of the volume of $O_{2}$ moleculesto the total volume of gas at $S T P$ is:

0.09 %

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0.9 %

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0.009 %

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0.045 %

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Solution

The correct option is A 0.09 %
Here, volume % $= \frac{v o l . o f O_{2} m o l e c u l e (O_{2})}{v o l . o f O_{2} m o l e c u l e a t S T P (O_{2})}$ $= \frac{\frac{4}{3} π \times 8 \times 10^{- 30} \times 10^{3}}{22.4 / N_{A}}$ $= 0.09$ %

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