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Question

Assuming that petrol is octane C8H18 and has density 0.8 g/ml, 1.425 litre of petrol on complete combustion will consume


A

50 mole of O2

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B

100 mole of O2

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C

125 mole of O2

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D

200 mole of O2

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Solution

The correct option is C

125 mole of O2


moctane=d×v

=0.8×1425

=1140gm

noctane =1140114=10 moles

C18H18+252O28CO2+9H2O

For 1 mole of octane 12.5 moles of oxygen is required so for 10 moles of octane 125 moles of oxygen is required.


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