You visited us 1 times! Enjoying our articles? Unlock Full Access!

Shear Strain

Assuming that...

Question

Assuming that shear stress of base of a mountain is equal to force per unit area to its weight, calculate the maximum possible height of a mountain on the earth if breaking stress of a typical rock is $30 \times 10^{7} N m^{- 2}$ and specific gravity is $3 \times 10^{3} k g / m^{3}$ .

10 km

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

8 km

No worries! We‘ve got your back. Try BYJU‘S free classes today!

7 km

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6 km

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 10 km
(a) $p = \frac{W}{A} = h p g \leq B r e a k i n g s t r e s s$
or $h \leq \frac{B r e a k i n g s t r e s s}{p g} = \frac{3 \times 10^{8}}{3 \times 10^{3} \times 10}$
$h \leq 10 k m$

Suggest Corrections

Similar questions

km

3 \times 10^{8} {Nm}^{- 2}

3

3 \times 10^{8} N m^{- 2}

3 \times 10^{3} k g m^{- 3}

g = 10 m s^{- 2}

10^{6} N / m^{2}

3 \times 10^{3} k g / m^{3}

(in m)

[P_{atmospheric} = 100 kPa, ρ = 1.8 \times 10^{3} {kg/m}^{3}

σ = 3.7 MPa]

10^{9}

3 \times 10^{3} K g / m^{3}

Join BYJU'S Learning Program