Assuming that the charges of an electron is $1.6 \times 10^{- 19}$ C, the number of electrons passing through a section of wire per second, when the wire carries a current of one ampere is :

0.625 \times 10^{19}

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1.6 \times 10^{- 19}

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1.6 \times 10^{19}

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0.625 \times 10^{- 17}

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Solution

The correct option is A $0.625 \times 10^{19}$
Given,
e $= 1.6 \times 10^{- 19}$ C, $I$ $= 1 A$
Let number of electrons per second be $N$ .
The current is defined as rate of flow of charge,
I $= \frac{q}{t}$
Also,
q $= N e$
Hence,
$I$ $= \frac{N e}{t}$
Substituting values,
1 A $= \frac{N \times 1.6 \times 10^{- 19}}{t}$
N $= 0.625 \times 10^{19}$

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Assuming that the charges of an electron is 1.6×10−19 C, the number of electrons passing through a section of wire per second, when the wire carries a current of one ampere is :

The correct option is A 0.625×1019Given,e =1.6×10−19 C, I =1 ALet number of electrons per second be N.The current is defined as rate of flow of charge,I =qtAlso,q=NeHence,I =NetSubstituting values,1 A =N×1.6×10−19tN =0.625×1019

Assuming that the charges of an electron is $1.6 \times 10^{- 19}$ C, the number of electrons passing through a section of wire per second, when the wire carries a current of one ampere is :