Assuming that the degree of hydrolysis is small, the $p H$ of 0.1 M solution of sodium acetate $(K_{a} = 1.0 \times 10^{- 5})$ will be:

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Solution

The correct option is C 9
For a salt of strong base and weak acid,

$p H = p K_{w} - \frac{1}{2} [p K_{w} + l o g K_{a} - l o g C]$
$p K_{w} = 14, K_{a} = 1.0 \times 10^{- 5}$ and $C = 0.1 M$
$p H = 14 - \frac{1}{2} [14 + l o g 10^{- 5} - l o g 10^{- 1}]$
$p H = 14 - \frac{1}{2} [14 - 5 + 1]$
$p H = 14 - \frac{1}{2} [10]$
$p H = 14 - 5$
$p H = 9$

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