Assuming that the mass m of the largest stone that can be moved by a flowing river depends upon the velocity v of the water, its density ρ and the acceleration due to gravity g. Then m is directly proportional to
A
v3
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B
ρ6
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C
g−4
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D
v6
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Solution
The correct option is Dv6 As per the question we can write m∝vaρbgc ⇒[M]=[LT−1]a[ML−3]b[LT−2]c ⇒[M1L0T0]=[MbL(a−3b+c)T(−a−2c)] On comparing L.H.S and R.H.S we get b=1....(i) a−3b+c=0⇒a+c=3.....(ii) and, −a−2c=0.....(iii) On solving (ii) & (iii) we get c=−3,a=6 So, the relation would be m∝v6ρg−3