Assuming that the $n -$ channel MOSFET is ideal, with a threshold voltage of 1 V, the voltage $V_{a b}$ is ________V.

0

Open in App

Solution

The correct option is A 0
Given circuit NMOS has
$V_{t h} = + 1 V$
Gate voltage, $V_{G} = 2 V$
Source voltage, $V_{s} = 0 V$
So, $V_{G S} = 2 - 0 = 2 V$
Also, $V_{D S (s a t)} = V_{G S} - V_{t h}$
$= 2 - 1 = 1 V$
Since 10 V is applied across drain-source terminal,
$V_{D S} > V_{D S (s a t)}$
NMOS operates in saturation; channel conductivity is high and high current flows through drain to source and it acts as short circuit.
$∴ V_{a b} = 0$

Suggest Corrections

Similar questions

An n-channel MOSFET is biased with V_{G S} = 2 V, V_{D S} = 1 V and the value of threshold voltage for the MOS transistor is 1.5 V. Then MOSFET is operating in

A n i d e a l n - c h a n n e l M O S F E T h a s t h e f o l l o w i n g p a r a m e t e r s, t h r e s h o l d v o l t a g e V_{T} = 0.65 V a n d o x i d e t h i c k n e s s i s 0.4 n m . I t i s f o u n d t h a t t h e M O S F E T o p e r a t i n g i n s a t u r a t i o n r e g i o n w i t h V_{D S} = 6 V . T h e n t h e p o w e r d i s s i p a t i o n i n t h e M O S F E T w i t h V_{G S} = 4 V i s μ_{n} C_{a x} \frac{W}{L} = 1.5 \times 10^{- 3} A / V^{2},

V_{0}

Consider the n-channel and p-channel MOSFETs, if these are to have equal drain currents when operated in the saturation mode with overdrive voltages of the same magnitude. Then the ratio of width of p-channel MOSFET to n-channel MOSFET is______(Assume, μ_{p} = 0.4 μ_{n}, L_{n} = L_{p})

Join BYJU'S Learning Program