Assuming the coefficient of friction between the road and tyres of a car to be 0.5, the maximum speed with which the car can move round a curve of 40.0 m radius without slipping, if the road is unbanked, should be

25 m/s

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19m/s

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14m/s

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11m/s

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Solution

The correct option is C
14m/s

$v = \sqrt{μ g r} = \sqrt{0.5 \times 9.8 \times 40} = \sqrt{196} = 14 m / s$

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Assuming the coefficient of friction between the road and tyres of a car to be 0.5, the maximum speed with which the car can move round a curve of 40.0 m radius without slipping, if the road is unbanked, should be

The correct option is C 14m/s v=√μgr=√0.5×9.8×40=√196=14 m/s

The correct option is C
14m/s

$v = \sqrt{μ g r} = \sqrt{0.5 \times 9.8 \times 40} = \sqrt{196} = 14 m / s$