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Question

Assuming the density of air to be 1.295kg/m3, find the fall in the barometric height in mm of Hg at a height of 107 m above sea level. Take density of mercury = 13.6×103kg/m3.

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Solution

First, let us assume that the height above the sea level is h = 107 m.

PhPsea=ρairgh

ρHgghfρHgghi=ρairgh

h=ρairghρHgg=1.295×10713.6×103=0.010 m.

h=0.010 m of Hg.


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