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Question

Assuming the expression for the pressure exerted by the gas on the walls of the container, it can be shown that pressure is

A
[13]rd kinetic energy per unit volume of a gas
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B
[23]rd kinetic energy per unit volume of a gas
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C
[33]th kinetic energy per unit volume of a gas
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D
32× kinetic energy per unit volume of a gas
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Solution

The correct option is A [23]rd kinetic energy per unit volume of a gas
Kinetic energy of the gas K=12mv2rms
Rms velocity of gas molecules vrms=3RTm
K=12m.3RTm=32RT
From ideal gas equation, RT=PV
K=32PV
Thus we get pressure of the gas P=23KV


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