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Question

Assuming the radius of nucleus to be equal to R=1.3A1/3×1015m, where A is its mass number, evaluate the density of nuclei and the number of nucleons per unit volume of the nucleus. Take mass of one nucleon=1.67×1027kg .

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Solution

For a nucleus having mass number A that is total nucleons A
the radius is R=1.3A1/3×1015m
So volume will be V=4π3(1.3)3A×1045m3=9.2A×1045m3
Density=mass/volume=A×1.67×1027kg9.2A×1045=1.8×1027kg/m3
Number of nucleons per unit volume is A/V=A9.2A×1045=1.09×1044/m3

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