Question

Assuming the volume is held constant, what happens to the pressure of gas when the absolute temperature doubles?

• A. It is doubled
• B. It is quadrupled
• C. It is halved
• D. None of these

Answer 1

The correct option is A It is doubled

The ideal gas equation is, $PV=nRT$.

When $V,R$ and $n$ are constants, Pressure becomes directly proportional to the Temperature.

⇒ $P\propto T$

⇒$\frac{P_1}{T_1}$ = $\frac{P_2}{T_2}$ (Gay-Lussac's law)

Now, when temperature is doubled i.e. $T_2$ = 2$T_1$

$P_2$ = $\frac{T_2}{T_1}$ x $P_1$

⇒ $P_2$ = $2P_1$

Thus, option A is correct.