Question

At $0.1atm$ and ${25}^{\circ }C$, compressibility factor of four gases $A,B,C$ and $D$ are $0.25,1.3,1and0.7$ respectively. The gas which is most easily liquifiable at ${25}^{\circ }C,$ will be.

• A. $D\left(g\right)$
• B. $C\left(g\right)$
• C. $B\left(g\right)$
• D. $A\left(g\right)$

Answer 1

The correct option is D $A\left(g\right)$

Less will be the value of $Z$, more will be negative deviation, hence more will be the attractive forces.
$Z<1$ (negative deviation)
Attractive force will dominate so, $A\left(g\right)$ will be more compressible / liquifiable.