At $0^{\circ}$ and $760 m m$ Hg pressure, a gas occupies a volume of $100 c m^{3}$ . Kelvin temperature of the gas is increased by one-fifth and the pressure is increased one and a half times. Calculate the final volume of the gas

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Solution

The correct option is A 80
$G i v e n T_{1} = 0^{0} = 273 K a n d P_{1} = 760 m m o f H g T_{2} = 273 + \frac{273}{5} = 327.6 K a n d P_{2} = 760 + \frac{760}{2} = 1140 m m o f H g A S p e r i d e a l g a s e q u a t i o n P V = n R T a s i n b o t h t h e c a s e s g a s i s s a m e t h a n, \frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}} V_{2} = \frac{327.6 \times 760 \times 100}{273 \times 1140} = 80 {c m}^{3}$

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At 0∘ and 760mm Hg pressure, a gas occupies a volume of 100cm3. Kelvin temperature of the gas is increased by one-fifth and the pressure is increased one and a half times. Calculate the final volume of the gas

The correct option is A 80GivenT1=00=273KandP1=760mmofHgT2=273+2735=327.6KandP2=760+7602=1140mmofHgASperidealgasequationPV=nRTasinboththecasesgasissamethan,P1V1T1=P2V2T2V2=327.6×760×100273×1140=80cm3

At $0^{\circ}$ and $760 m m$ Hg pressure, a gas occupies a volume of $100 c m^{3}$ . Kelvin temperature of the gas is increased by one-fifth and the pressure is increased one and a half times. Calculate the final volume of the gas