At $0^{o} C$ and 2 atm pressure, the volume of 1 gram of a diatomic gaseous element is 350 $m l$ . Weight of 1 atom of the element in grams is:

2.67 \times 10^{- 23}

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3 \times 10^{- 10}

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6 \times 10^{- 23}

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4 \times 10^{- 20}

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Solution

The correct option is D $2.67 \times 10^{- 23}$

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Similar questions

7.23 \times 10^{23}

3.01 \times 10^{23}

0^{\circ} C

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